Question

Find the center, (H,K) (x+3)^2+(y+1)^2=9

Answer 1

The center of the equation of the circle will be (h, k) = ( -3. -1).

What are a circle and its equation?

A circle can be characterized by its center's location and its radius's length.

Let the center of the considered circle be at (h,k) coordinate.

Let the radius of the circle be 'r' units.

Then, the equation of that circle would be:

$(x-h)^2 + (y-k)^2 = r^2$

We have been given an equation of the circle as

$(x+3)^2+(y+1)^2=9$

By comparing the equation with general equation of the circle

we get,

h = -3

k = -1

r = 3

So, the center of the equation will be (h, k) = ( -3. -1).

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