100point
Answer ASAP
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Answer:
a) 0.96 s (2 d.p.)
b) 2.78 s (2 d.p.)
Step-by-step explanation:
Given equation for Period T:
[tex]T=2 \pi \sqrt{\dfrac{L}{980}[/tex]
Part (a)
Given:
Substitute the given value into the formula and solve for T:
[tex]\implies T=2 \cdot 3.14 \cdot\sqrt{\dfrac{23}{980}[/tex]
[tex]\implies T=6.28\dfrac{\sqrt{115}}{70}[/tex]
[tex]\implies T=\dfrac{157\sqrt{115}}{1750}[/tex]
[tex]\implies T=0.9620785322[/tex]
[tex]\implies T=0.96\: \sf s \: \:(2 \:d.p.)[/tex]
Part (b)
Given:
Substitute the given value into the formula and solve for T:
[tex]\implies T=2 \cdot 3.14 \cdot\sqrt{\dfrac{192}{980}[/tex]
[tex]\implies T=6.28{\sqrt{\dfrac{48}{245}}[/tex]
[tex]\implies T=\dfrac{628\sqrt{15}}{875}[/tex]
[tex]\implies T=2.779695476[/tex]
[tex]\implies T=2.78\:\sf s \: \:(2\:d.p.)[/tex]