find the x step by step
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Angles are equal as it's parallelogram
Answer:
x = 3
Step-by-step explanation:
Assuming the given shape is a rhombus.
Properties of a rhombus
As there is a reflection of symmetry over the diagonals, the diagonals bisect the vertices, i.e. the diagonal divides the vertices into 2 equal angles. Therefore, the angles either side of the diagonal at each vertex are equal.
Therefore:
[tex]\implies 6x^2-15=5x^2-2x[/tex]
Rearrange to create a quadratic (equal to zero):
[tex]\implies 6x^2-15-5x^2+2x=0[/tex]
[tex]\implies x^2+2x-15=0[/tex]
Solve the quadratic to find the value of x:
[tex]\implies x^2+2x-15=0[/tex]
[tex]\implies x^2+5x-3x-15=0[/tex]
[tex]\implies x(x+5)-3(x+5)=0[/tex]
[tex]\implies (x-3)(x+5)=0[/tex]
Therefore:
[tex](x-3)=0 \implies x=3[/tex]
[tex](x+5)=0 \implies x=-5[/tex]
Substitute the found values of x into one of the expressions:
[tex]x=3 \implies 6(3)^2-15=39[/tex]
[tex]x=-5 \implies 6(-5)^2-15=135[/tex]
Therefore, the options for the angles are 39° or 135°.
From inspection of the diagram, the angles are clearly acute (less than 90°), therefore the only appropriate value of x is 3.