Question

Which shows the correct substitution of the values a, b, and c from the equation 0=-3x² - 2x + 6 into the
quadratic formula?
Quadratic formula: x=
-b±√√b²-4ac
2a
x = −(−2) ± √(−2)² − 4(− 3)(6)
2(-3)
x= -2±√2²-4(-3)(6)
2(-3)
x==(-
x = −(−2) ± √(-2)² − 4(3)(6)
2(3)
-2±√√2²-4(3)(6)
(=
2(3)

Answer 1

Answer: $x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4(-3)(6)}}{2(-3)}$

Step-by-step explanation:

a = -3 , b = -2, and c = 6.