Respuesta :
For a system PCl3(g) + Cl2(g) PCl5(g) at equilibrium at 25°C, for which H° = –92.5kJ at 25°C, the ratio of the partial pressure of PCl5 to the partial pressure of PCl3 is will increase
What is the ratio of the partial pressure of PCl5 to the partial pressure of PCl3?
Generally, the equation for chemiecal reaction is mathematically given as
PC3 (g) + C₁₁₂ (g) = PC15 (g) 3
Assuming the addition of some Cl2 gas. The reaction will shift to the right at the invariant volume temperature, maintaining equilibrium. This results in a rise in P9Cl5(g) and a fall in PpCl3(g).
PpCl (g) /PpCl (g) will increase
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The ratio of the partial pressure of PCl₅ to the partial pressure of PCl₃ is will increase for a system PCl₃ (g) + Cl₂ (g) --> PCl₅ (g) at equilibrium at 25°C, for which H° = –92.5kJ at 25°C when some Cl₂ (g) is added at constant volume and temperature.
What is the ratio of the partial pressure of PCl₅ to the partial pressure of PCl₃?
Generally, the equation for chemical reaction is mathematically given as ;
PCl₃ (g) + Cl₂ (g) --> PCl₅ (g)
Assuming the addition of some Cl₂ gas,
The reaction will shift to the right at the constant volume and temperature, maintaining equilibrium.
This results in a rise in PCl₅ (g) and a fall in PCl₃(g).
Hence, the ratio of the partial pressure of PCl₅ to the partial pressure of PCl₃ is will increases
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