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A vehicle of mass 2000 kg travels at a speed of 72 km/h. Determine your kinetic energy?​

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[tex]\large \bold {ANSWER}[/tex]

✏️ The value of kinetic energy is 400000 J.

[tex]\large \bold {SOLUTION}[/tex]

Solve by applying the kinetic energy formula, where Ec is kinetic energy, m is mass, v is velocity in m/s. Remember that 72 km/h is 20 m/s.

[tex]\begin{gathered}\Large \text {$ \sf Ec = \dfrac {m \times v^2}{2} $}\\\\\Large \text {$ \sf Ec = \dfrac {2000 \times 20^2}{2} = 400000 $ J}\end{gathered}[/tex]

Answer:

400 000 joules

Explanation:

Kinetic energy is measured in joules which has units of  kg - m^2 / s^2

so you will need to convert 72 km/hr to   m/ s

   =    72000 m / 3600 s = 20 m/s

KE = 1/2 m v^2

    = 1/2 (2000)(20^2) = 400 000 Joules

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