The following equation shows the position of a particle in time t, x=at²i + btj where t is in second and x is in meter. A=2m/s², b=1m/s. Find
A, the average velocity of the particle in the time interval t₁=2sec and t₂=3sec
B, the velocity and acceleration at any time t.
C, the average acceleration in the time interval given in part (a)​

Respuesta :

The average velocity is 4i m/sec ,  the average acceleration is 4i

What is a Vector ?

A vector is an object that has both magnitude and direction.

It is given that

x=at²i + btj

where t is in second and x is in meter.

The average velocity is given by dx/dt

dx/dt = 2at i + b j

dx/dt = 2 * 2 * t i +1 j

dx/dt = 4t i +j

dx/dt in the time interval of 2 to 3 sec is

at 2 sec,

dx/dt = 4 * 2 i +j = 8i +j

at 3 sec ,

dx/dt = 4 * 3 i + j = 12i+j

Therefore the average velocity is

(12i +j - 8i -j)/ (3-2) = 4i

The velocity at any given time is dx/dt = 4t i +j

The acceleration at any given time is d²x/dt²

d²x/dt² = 4 i

the average acceleration in the time interval  t₁=2sec and t₂=3sec

Average Acceleration =  4i

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