Question

Calculate the value of delta;: y²+8y+20=0​

Answer 1

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$\large \bold {ANSWER}$

$\LARGE\displaystyle\text{ \begin{gathered}\boxed{\boxed{\:\:\:\bf \Delta = -16\:\:\:}}\end{gathered} }$

$\large \bold {SOLUTION}$

➢ Let the second degree equation be:

$\LARGE\displaystyle\text{ \begin{gathered}\tt y^{2} + 8y + 20 = 0\end{gathered} }$

➢ Whose coefficients are:

$\begin{gathered}\LARGE\begin{cases}\tt a = 1\\\tt b = 8\\\tt c = 20\end{cases}\end{gathered}$

➢ To calculate the delta value, we must use the following formula:

$\LARGE\displaystyle\text{ \begin{gathered}\tt \Delta = b^{2} - 4ac\end{gathered} }$

$\LARGE\displaystyle\text{ \begin{gathered}\tt = 8^{2} - 4\cdot1\cdot20\end{gathered} }$

$\LARGE\displaystyle\text{ \begin{gathered}\tt = 64 - 80\end{gathered} }$

$\LARGE\displaystyle\text{ \begin{gathered}\tt = -16\end{gathered} }$

➢ Therefore, the delta value is:

$\LARGE\displaystyle\text{ \begin{gathered}\tt \Delta = -16\end{gathered} }$