Answer:
[tex]\sf 1. \quad \tan(B)=\dfrac{4}{3}[/tex]
[tex]\sf 2. \quad \tan(A)=\dfrac{7}{2}[/tex]
[tex]\sf 3. \quad \angle A[/tex]
Step-by-step explanation:
Acute angle: an angle less than 90°
Tan trigonometric ratio
[tex]\sf \tan(\theta)=\dfrac{O}{A}[/tex]
where:
Question 1
Refer to the first attached diagram.
If tan(A) = 3/4 then the side opposite ∠A is 3 units, and the side adjacent ∠A is 4 units.
Therefore:
[tex]\implies \sf \tan(B)=\dfrac{4}{3}[/tex]
Question 2
Refer to the second attached diagram.
If tan(B) = 2/7 then the side opposite ∠B is ,and the side adjacent ∠B is 7.
Therefore:
[tex]\implies \sf \tan(A)=\dfrac{7}{2}[/tex]
Angle A would be bigger (see second attachment).