Question

Veronika’s five test scores are 59, 80, 95, 88, and 93. If the outlier of 59 is removed, what is the mean absolute deviation of the remaining four test scores

Answer 1

Answer:

Mean deviation of 80, 88, 93, 95 is 5

Step-by-step explanation:

Step 1: find the mean

Mean = Sum of items/ Number of items

Mean = 80+88+93+95 = 356

Mean = 356 / 4 = 89

Step 2: find the mean deviation

Mean Deviation = ∑i = 0n |xi − μ| / N

Mean Deviation = | (89-80) + (89-88) + (89-93) + (89-95) | /4

Mean Deviation = 5