The power the swimmer must provide to overcome that drag force is 50 W.
What is work done?
Work done is equal to product of force applied and distance moved.
Work = Force x Distance
Given is an athlete, swimming at a constant speed, covers a distance of 203 m in a time period of 5 minutes and 50 seconds = 350 seconds. The drag force exerted by the water on the swimmer is 86.0 N.
Work done by drag force is W= F x d
So, W = 86 N x 203 m
W = 17.458 kJ
Power , a swimmer is provided P = Work done/ Time
P = 17458 / 350
P = 50 W
Thus, the power, the swimmer must provide to overcome that drag force is 50 W.
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