The two-dimensional net of this pyramid that is surface area will be 34,416 square feet.
Suppose the base of the pyramid has length = L units, width = W units, slant height = K units, and the height of the pyramid is of H units.
The surface area of the pyramid will be
SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)
The largest pyramid at Giza is a square pyramid. It has a base of 756 feet and a slant height of 612 feet.
We have
L = W = 27.5 feet
Then the two-dimensional net of this pyramid that is surface area will be
SA = 2(1/2 × B × K) + 2(1/2 × L × K) + (L × B)
SA = 4(1/2 × 27.5 × 612) + 756
SA = 33,660 + 756
SA = 34,416 square feet
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