Question

May someone help me asap! I have been trying to solve this equation and keep getting the wrong answer. Consider this quadratic equation. 3x^2 + 4x - 12= 13 Which equation correctly applies the quadratic formula?

Answer 1

Answer:

The second one

Step-by-step explanation:

remember the quadratic formula for this.

-b+-sqrtb^2-4ac/2a

then just apply the numbers in using ax^2+bx+c.

don't forget that you would do -13 on both sides to set it to 0

Answer 2

Answer:

B

Step-by-step explanation:

First, you need to simplify your equation so that all the parts are on the same side. You do this by subtracting 13 on both sides:
$3x^{2} + 4x - 12 -13 = 0$
$3x^{2} + 4x -25 = 0$

Now, you can plug these values into the quadratic formula. The number with the $x^{2}$ is a, the number with the $x$ is b, and the number without a variable is c. The quadratic equation is as follows:

$\frac{-b + \sqrt{b^{2} - 4ac} }{2a}$

When you plug all these values in, you get answer choice B.

Also note that the equation should be -b ± (plus or minus) but I could not include it in the equation.