Question

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.
Tariq designed the pool shown. The owner of the pool has one square cover to use. Find the area of the space that needs to be covered. (The four corners are squares.)

The area that needs to be covered is

ft2.

Answer 1

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$\mathbb{PROBLEM:}$

A square with side lengths 12 feet. 4 2 feet by 2 feet squares are cut out of each corner of the square.

• Find the Area of the Space.

$\mathbb{SOLUTION:}$

• $\bold{A = Length \: x \: Width}$

• $\bold{A = 12 \: ft \: x \: 4.2 \: ft }$

• $\blue{\bold{A = 50.4 \: ft} }$

• $\bold{ A\red{ = 50.4 } \: x \: 2 \: ft}$

• $\boxed{ \bold{ A = 100.80 ft²}}$

"If the 2 is quantity use multiply it again"

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NOTE:The way to solve a square area is by measuring the length and width of your area then multiplying those two numbers together to get the area in feet squared (ft2).

"Problem has been solve"

(ノ^_^)ノ

Answer 2

$\large\bold{SOLUTION}$

GIVEN :-

• A square with side lengths 12 feet.
• 4.2 feet by 2 feet squares are cut out of each corner of the square .

FIND :-

• Find the area of the space that needs to be covered .

By finding the area of the space that needs to be covered we must use multiplication and multiply the given measurements .

$\bold{Formula:}$

$\qquad \boxed{ \bold{ \: \: Area = Length \times Width \: \: }}$

Now let's start solving :-

$\quad \sf \implies{Area = Length \times Width}$

$\quad \sf \implies{Area = 12ft \times 4.2ft}$

$\quad \sf \implies{Area = 12feet \times 4.2ft = \pmb{50.4 ft}}$

$\quad \sf \implies{Area = 50.4ft \times 2ft = \pmb{100.80ft^2}}$

Therefore, the area of the space that needs to be covered is 100.80ft² .

$\underline{ \rule{185pt}{3pt}}$