Question

A satellite orbits the Earth with an elliptical orbit modeled by x squared over 43 million eight hundred twenty four thousand four hundred plus y squared over forty seven million one hundred ninety six thousand nine hundred equals 1 comma where the distances are measured in km. The Earth shares the same center as the orbit. If the radius of the Earth is 6,370 km, what is the maximum distance between the satellite and the Earth?

250 km
500 km
6,620 km
6,870 km

Answer 1

"For a satellite orbit, the Earth with an elliptical orbit modeled by..." the maximum distance between the satellite and the Earth is

D= 510 km. Option B. This is further explained below.

What is Kepler Orbit?

Generally, In the study of astrodynamics, an ellipse of the satellite is often referred to as a Kepler Orbit

The function of the elliptical orbit is

$\frac{(x-h)^2}{a^2}+\frac{(x-k)^2}{b^2}=1$

compared to

$\frac{(x^2)^2}{47334400}+\frac{(y^2)^2}{43956900}=1$

Hence

a = √(47,334,400 km²)

a= 6,880 km.

In conclusion, The distance of the satellite above the Earth's surface.

D = a - r

D= 6,880 km - 6,370 km

D= 510 km

Read more about elliptical orbit

at brainly.com/question/13999216

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Answer 2

"For a satellite orbit, the Earth with an elliptical orbit modeled by..." the maximum distance between the satellite and the Earth is D= 510 km. Option B.

What is Elliptical Orbit?

An elliptic orbit or elliptical orbit is a Kepler orbit with an eccentricity of less than 1; this includes the special case of a circular orbit, with eccentricity equal to 0.

The function of the elliptical orbit is

$\frac{{(x-h)}^2}{a^2}+ \frac{{(y-k)}^2}{b^2} = 1$

compared to

  √($\frac{({x^2)}^2}{47,334,400} + \frac{({y^2)}^2}{43956900} = 1$

a = √(47,334,400 km²)

a= 6,880 km.

Now,

D = a - r

D= 6,880 km - 6,370 km

D= 510 km

Learn more about elliptical orbit from:

brainly.com/question/13999216

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