The foci of the hyperbola represented by (0, –6) and (0, 6). Then the correct option is B.
The hyperbola is the locus of a point such that the difference of distance from point P to two non-movable points. These two points are called foci of hyperbola.
The equation of the parabola is given below.
5y² – 4x² – 80 = 0
Then the equation can be written as
y² / 4 – x² / 5 – 4 = 0
y² / 16 – x² / 20 = 1
Then the value of eccentricity will be
a² = 16 and b² = 20
Then we have
e = √[1 + (b² / a²)]
e = √[1 + (20 / 16)]
e = 1.5
Then the focus of the parabola will be
⇒ (0, ±ae)
⇒ (0, ± 4 x 1.5)
⇒ (0, ±6)
⇒ (0, –6) and (0, 6)
Then the correct option is B.
More about the hyperbola link is given below.
https://brainly.com/question/12919612
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