Question

A father is five times as old as his son . their total age in 10 years time will be 80 years . How old is the son now?
a father is a father is 5 times as old as his son that total age in 10 years time will be 8 years how old is the Son now ​

Answer 1

The son is 10 years old now.

Calculating the age of the son :

Let the age of the son be x years old.

Given :

Father's age will be 5x years.

In 10 years the sum of son and father's age is 80 years.

Son's age after 10 years = x+10

Father's age after 10 years= 5x+10

This can be expressed in an equation,

$x + 10 + 5x + 10 = 80$

$6x + 20 = 80$

$6x = 80 - 20 = 60$

$6x = 60$

$x = 60/6 = 10$

Therefore the present age of the son is 10 years and the present age of father is 5 x 10 = 50 years.

To learn more about how to calculate the age of people refer to :

https://brainly.com/question/13517515

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Answer 2

Step-by-step explanation:

father = 5X

son =X

age in ten years

(X+10)+(5X+10)=80

expand

5X+X+10+10=80

6X+20=80

6X=80-20

6X=60

X=10

substitute into the equation

(10+10)+(5*10+10)

20+50+10 =80

currently, the son is 10 years

while the father is 5*10=50 years