The car travelled farther after the brakes were applied is car 1.
The speed of any moving object is the ratio of the distance covered and the time taken to cover that distance.
Speed s = distance d / time t
A driver of a car travelling at 52 km/ h=14.44 m/s applies the brakes and accelerates uniformly in the opposite direction. The car stops in 5 s. Another driver going at 3 km/h =0.833 m/s in another car applies his brakes slowly and stops in 10 s.
For both the cars, the final speed is zero.
Using the first equation of motion, we have
v = u +at
For car 1,
0 = 14.44 +a x 5
a = -2.88 m/s²
For car 2,
0 = 0.833 +a x 10
a = -0.0833 m/s²
Using the third equation of motion, we have
v² -u² =2as
For car 1,
0 - (14.44)² = 2 x (-2.88) x s
s = 36.200 m
For car 2,
0 - (0.833)² = 2 x (-0.0833) x s
s = 4.165 m
Thus, the larger distance traveled by the first car.
Learn more about speed.
https://brainly.com/question/7359669
#SPJ1