Question

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 30 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph's average speeds and velocities in jogging (a) from A to B and (b) from A to C?​

Answer 1

Joseph's average speeds and velocities in jogging from A to B will be  2 m/sec and 2 m/sec and from A to C will be  1.90 m/sec and 0.95 m/sec.

What is the average velocity?

The average velocity is the ratio of the total distance traveled to the total time taken by the body. Its unit is m/sec.

From points A to B;

Distance covered,d=300m

Displacement,D=300m

Time taken,t=2 min 30 sec

                    =(2×60)+30

                      =150 sec

The average speed is found as;

$\rm S_{avg} = \frac{d}{t} \\\\ \rm S_{avg} = \frac{300}{150} \\\\ S_{avg} =2 \ m/sec$

The average velocity is found as;

$\rm V_{avg} = \frac{D}{t} \\\\ V_{avg} =\frac{300}{150} \\\\ V_{avg} =2 \ m/sec$

Hence, joseph's average speeds and velocities in jogging from A to B will be 2 m/sec and 2 m/sec.

(b)From points A to C;

Distance covered;

d'=300+100=400m

Displacement

D'=300−100

D'=200m

Time taken;

t;=3 min 30 sec

t'=(3×60)+30

t'=210 sec

The average speed is found as;

$\rm S_{avg} = \frac{d}{t} \\\\ \rm S_{avg} = \frac{400}{210} \\\\ S_{avg} =1.90 \ m/sec$

The average velocity is found as;

$\rm V_{avg} = \frac{D}{t} \\\\ V_{avg} =\frac{200}{210} \\\\ V_{avg} =0.95 \ m/sec$

Hence, joseph's average speeds and velocities in jogging from A to C will be 1.90 m/sec and 0.95 m/sec.

To learn more about the average velocity, refer to the link;

https://brainly.com/question/862972

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