Question

A cyclist rode the first 26​-mile portion of his workout at a constant speed. For the 20​-mile cooldown portion of his​ workout, he reduced his speed by 3 miles per hour. Each portion of the workout took the same time. Find the​ cyclist's speed during the first portion and find his speed during the cooldown portion.

Answer 1

The speed of the cyclist during the first portion is 13 mph and during the cooldown period is 10 mph.

To find the speed of the cyclist during each of the portions covered:

Let x be the speed of the cyclist.

We know that, speed=distance/time or time=distance/speed.

Applying this in the given situation,

First portion:

time = 26/x

Cooldown portion:

time = 20/x-3 as the speed is reduced by 3

Since each portion of the workout took the same time,

26/x = 20/x-3

26x - 78 = 20x

6x = 78

x = 13

Hence, the speed during the first portion is 13 mph.

As the speed was reduced by 3 during the cooldown portion,

speed during this portion = 13 - 3 = 10 mph.

Therefore, the speed of the cyclist during the first portion is 13 mph and during the cooldown period is 10 mph.

To know more about the relationship between distance and speed, refer

https://brainly.com/question/23774048

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