Factors of 105:
1, 3, 5, 7, 15, 21, 35 and 105
35 is the highest factor, and closest to 40, so let's try that.
40 - 35 = 5 years
8 - 5 = 3 years (Sons age five years ago)
35 x 3 = 105
(35 is the father's age, 3 is the child's age)
Answer:
The year is 5 years from the present date.
Would appreciate brainliest if this helped.
Answer:
5 years ago
Step-by-step explanation:
let x be the number of years ago , then
(40 - x)(8 - x) = 105 ← expand left side using FOIL
320 - 48x + x² = 105 ( subtract 105 from both sides )
x² - 48x + 215 = 0 ← in standard form
(x - 43)(x - 5) = 0 ← in factored form
equate each factor to zero and solve for x
x - 43 = 0 ⇒ x = 43
x - 5 = 0 ⇒ x = 5
x ≠ 43 , then x = 5
the product of their ages 5 years ago was 105 , that is
40 - 5 = 35 and 8 - 5 = 3 ⇒ 35 × 3 = 105
