Answer:
$2800
Step-by-step explanation:
let x represent the amount earned on the sale of a car
let y represent the amount earned on the sale of a truck
6x+3y=4800-eqn 1
8x+y=4600-eqn 2
Make y the subject of eqn 2
y=4600-8x
Plug y=4600-8x into eqn 1
6x+3(4600-8x)=4800
6x+13800-24x=4800
13800-4800=18x
18x=9000
x=9000/18=500
Now plug the value of x into eqn 2
8(500)+y=4600
4000+y=4600
y=600
So the amount earned on the sale of a car is $500 and $600 on the sale of a truck
Therefore,if 2cars and 3trucks are sold then
2($500)+3($600)
$1000+$1800
=$2800