Question

Use the distance formula to find the perimeter
of the triangle with vertices at the points
(-1,0), (2, 0), and (2, 7). Round to two decimal
places if necessary.

Answer 1

Answer:

See below.

Step-by-step explanation:

$(-1,0) \text{ vs} ( 2,0)$

$\sqrt{ ( (-1-2)^2 + (0-0)^2) }= \sqrt{( (-3)^2 + 0^2) }=\sqrt{( 9+0)}= \sqrt{(9) = 3}$

$(-1,0) \text{vs} ( 2,7)$

$\sqrt{( (-1-2)^2 + (7-0)^2) }= \sqrt{( (-3)^2 + (7)^2) }=\sqrt{( 9+49)} =\sqrt{(58)}$

(2,0) vs (2,7) has distance of 7

Answer is $10+\sqrt{58}$ (17.6157731058639082856614110271583)