Question

The area A of a trapezoid with parallel sides of lengths A andB and height H is a=1/2(a+b)h

Answer 1

Answer:

last option, 2A / (a + b) = h

Step-by-step explanation:

Answer 2

Answer:

$\sf D)\ \dfrac{2A}{a+b}=h\ \ \textsf{or}\ \ 2A\div(a+b)=h$

Step-by-step explanation:

Given: A = ½(a + b)h

We need to solve for h.

1. Rewrite the equation:

$\sf A=\dfrac{1}{2}(a+b)h \implies A=\dfrac{1}{2}h(a+b)$

2. Divide both sides by (a + b):

$\sf \\\implies \dfrac{A}{a+b}=\dfrac{\dfrac{1}{2}h(a+b)}{a+b}\\\\\implies \dfrac{A}{a+b}=\dfrac{1}{2}h$

3. Multiply both sides by 2:

$\sf \\\implies 2\left(\dfrac{A}{a+b}\right)=2\left(\dfrac{1}{2}h\right)\\\\\implies \dfrac{2A}{a+b}=h\ \ \textsf{or}\ \ 2A\div(a+b)=h$