Question

Find 2 consecutive even numbers such that the sum of the
greater number and twice the smaller number is 44.

Answer 1

Answer:

14,16

Step-by-step explanation:

Let x be the first even number.

Let y be the 2nd even number.

Given, y - x = 2 (Since they are 2 consecutive even numbers.)

rearranging the equation: y = x+2 (equation 1)

Also given,

$y+2x=44$ (equation 2)

Now we can substitute equation 1 into equation 2 to find x.

$x+2+2x = 44\\3x+2 = 44\\3x = 44-2\\3x=42\\x = \frac{42}{3} \\x = 14$

Given the smaller even number x, is 14, we will substitute x into equation1 to find y, the bigger even number.

y = 14+2

= 16

Therefore the 2 numbers are 14 and 16.

Answer 2

Answer:

14, 16

Step-by-step explanation:

Let the consecutive even numbers be (2x) and (2x+  2)

Twice the smaller number = 2*2x = 4x

Sum  = 44

4x  + 2x + 2 = 44

 Combine like terms

     6x + 2 = 44

Now, subtract 2 from both sides

              6x = 44 -2

              6x = 42

Divide both sides by 6

                x = 42/6

                x = 7

2x = 2*7 =14

2x + 2 = 2*7 + 2

          = 14 + 2

          = 16

             $\sf \boxed{\text{\bf Two consecutive even numbers are 14,16}}$