Answer:
[tex](s-1)(s+\frac{2{(s-1)}^{3}}{3})[/tex]
Step-by-step explanation:
1) Use Rule of One: [tex]{x}^{1}=x[/tex].
[tex]3s\times \frac{s-1}{3}+2\times \frac{{(s-1)}^{4}}{3}[/tex]
2) Cancel 3.
[tex]s(s-1)+2\times \frac{{(s-1)}^{4}}{3}[/tex]
3) Simplify [tex]2\times \frac{{(s-1)}^{4}}{3}[/tex] to [tex]\frac{2{(s-1)}^{4}}{3}[/tex].
[tex]s(s-1)+\frac{2{(s-1)}^{4}}{3}[/tex]
4) Factor out the common term s-1.
[tex](s-1)(s+\frac{2{(s-1)}^{3}}{3})[/tex]
