Question

A 46.2 L sample of gas exerts 237.4 mm Hg pressure at 139.2 ºC. What volume does the gas have at 702.4 mm Hg and 63.4 ºC?
A. 12.7
B. 2.40
C. 7.11
D. 112

Answer 1

7.111 L is the volume of gas with 702.4 mm Hg and 63.4 ºC.

What is an ideal gas equation?

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

Given data:

$V_1=46.2 L$

$P_1=237.4 mm Hg$

$T_1=139.2 ºC$

$V_2=?$

$P_2=702.4 mm Hg$

$T_2=63.4 ºC$

Using the given below formula:

$\frac{V_1 X P_1}{T_1} = \frac{V_1 X P_1}{T_2}$

$\frac{46.2 L X 237.4 \;mm Hg}{139.2} = \frac{V_2 X 702.4 mm Hg}{63.4 ºC}$

$V_2$ = 7.111 L

Hence, 7.111 L is the volume of gas with 702.4 mm Hg and 63.4 ºC.

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