The statement is false, because -2 is larger than -3.
We know that -3 is a lower bound for the real zeros of f(x).
So, if we define k as the smallest real zero of f(x), we have:
-3 < k.
Then we can take, for example, k = -2.5
That is an allowed value for the real zero.
In that case, -2 is not a lower bound, because is false that:
-2 < k = -2.5
Then if -3 is a lower bound for the real zeros of f(x), we can't assume that -2 is also a lower bound (because -2 is larger than -3).
If you want to learn more about lower bounds:
https://brainly.com/question/15991714
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