Question

What is the factored form of x³-1?
(x³-1)(x²+x+1)
(x-1)(x²-x+1)
(x-1)(x²+x+1)
(x³-1)(x²+2x+1)

Answer 1

Answer:

• $\sf C.\; \sf \left(x-1\right)\left(x^2+x+1\right)$

Step-by-step explanation:

$\sf x^3-1$

Let's rewrite 1 as 1 ^3.

$\sf x^3-1^3$

Now, we can apply the "Difference of Cubes Formula".

$\boxed{\sf x^3-y^3=\left(x-y\right)\left(x^2+xy+y^2\right)}$

• $\sf x^3-1^3=\left(x-1\right)\left(x^2+x+1\right)$

• $\sf \left(x-1\right)\left(x^2+x+1\right)$

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