Question

Two of the steps in the derivation of the quadratic formula are shown below.

Step 6: StartFraction b squared minus 4 a c Over 4 a squared EndFraction = (x + StartFraction b Over 2 a EndFraction) squared

Step 7: StartFraction plus or minus StartRoot b squared minus 4 a c EndRoot Over 1 a EndFraction = x + StartFraction b Over 2 a EndFraction

Which operation is performed in the derivation of the quadratic formula moving from Step 6 to Step 7?

Answer 1

The step 7 is a wrong step, because in the denominator 1 is written in place of 2.

What is a quadratic equation?

The quadratic equation is given as ax² + bx + c = 0. Then the degree of the equation will be 2. Then we have

Two of the steps in the derivation of the quadratic formula are shown below.

The equation is given below.

$\rm \dfrac{b^2 - 4ac}{4a^2} = \left (x + \dfrac{b}{2a} \right )^2$

Then the above equation can be written as

$\rm \pm \sqrt{ \dfrac{b^2 - 4ac}{4a^2}} = \left (x + \dfrac{b}{2a} \right )\\\\\\x = \dfrac{-b}{2a} \pm \sqrt{ \dfrac{b^2 - 4ac}{4a^2}}\\\\\\x = \dfrac{-b}{2a} \pm \dfrac{\sqrt{ b^2 - 4ac}}{2a}\\\\\\x = \dfrac{-b \pm \sqrt{ b^2 - 4ac}}{2a}$

The step 7 is a wrong step, because in the denominator 1 is written in place of 2.

More about the quadratic equation link is given below.

https://brainly.com/question/2263981

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Answer 2

Answer:

its C. taking the square root of both sides of the equation

Step-by-step explanation:

i got it right