The solution of x for both equations are ;
[tex]x = -1 \pm \sqrt{15} \\\\x = \dfrac{12 \pm \sqrt{-92}}{2}\\[/tex]
A quadratic equation is the second-order degree algebraic expression in a variable.
The standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
1.
[tex]x^2 + 2x + 1 = 17\\\\x^2 + 2x -16 = 0\\\\x = \dfrac{-2 \pm \sqrt{60}}{2}\\\\x = -1 \pm \sqrt{15}[/tex]
2.
x^2 - 12 x + 59 = 0
first we need to calculate the discriminant,
[tex]D= b^2 - 4 a c\\D= (-12)^2 -4 \times 1 \times 59\\\\D = -92[/tex]
Since D<0, the quadratic equation has no real solutions.
[tex]x = \dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}\\\\x = \dfrac{12 \pm \sqrt{-92}}{2}\\[/tex]
Learn more about quadratic equations;
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