A recent public opinion poll on gun control found that 60 people interviewed out of the 160 interviews supported new gun regulations. Please find the point estimate, and both the 90% & 95% confidence interval.

A confidence interval is defined as the range of values seen in our sample for which we anticipate discovering the value that best represents the population.

The 60 people interviewed out of the 160 interviews supported new gun regulations. Therefore, the number of successes is 60, while the number of trials is 160. Therefore we can write,

MLE = Success/ Trials = 60/160 = 0.375

Since the value of MLE is less than 0.5, therefore, the Wilson Estimation will be the best.

The Point estimate for 95% confidence interval(Z = 1.96) is,

PE = [S + (z²/2)] / (T + z²)

= [60 + (1.96)²/2)] / (160 + (1.96)²)

= 0.3779

The Point estimate for 90% confidence interval(Z = 1.645) is,

PE = [S + (z²/2)] / (T + z²)

= [60 + (1.645)²/2)] / (160 + (1.645)²)

= 0.3771

Learn more about Confidence intervals:

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