Question

n airplane took off from an airport and traveled at a constant rate and angle of elevation. When the airplane reached an altitude of 500 m, its horizontal distance from the airport was found to be 235 m. What was the angle when the airplane rose from the ground?

Answer 1

The angle of the plane when it rose from the ground is 64.8 degrees

Application of trigonometry identity

Given the following parameters from the question

Altitude of the airplane H =  500m

Horizontal distance from airport "d"  = 235

Required

angle of elevation

According to the trigonometry identity

tan x = opposite/adjacent

tan x = H/d
tan x = 500/235

tan x = 2.1277

x = arctan(2.1277)

x = 64.8 degrees

The angle of the plane when it rose from the ground is 64.8 degrees

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