The same 300kg of chocolate will last 4 days when the princess got 4 more dragons for her birthday, and she already had two pet dragons.
This was a work-time problem where the eating of chocolate was the work, the days showed the time, and the dragons were the workers, all equally efficient.
How are the work and time problems solved?
To solve work and time problems, we generally try to calculate the work done in 1 day by 1 person and then try to calculate work and time accordingly to the question.
How to solve the question?
In the question, we are informed that a princess has two pet dragons who can eat 300kg of chocolate in 12 days.
We are asked to find the number of days it will take the dragons to eat 300kg of chocolate if the princess got 4 more dragons for her birthday.
We are given that 2 dragons eat 300kg of chocolate in 12 days.
Therefore, 1 dragon eats 150kg of chocolate in 12 days.
Therefore, 1 dragon eats 150/12 kg of chocolate in 1 day.
Now, in the new case, the princess has got 2 + 4 = 6 dragons.
Therefore, the amount of chocolate that 6 dragons will it together in 1 day = (150/12)*6 = 75kg.
Therefore, 300kg of chocolate will last 300/75 days when the princess will have 6 dragons, that is, 4 days.
Therefore, the same 300kg of chocolate will last 4 days when the princess got 4 more dragons for her birthday, and she already had two pet dragons.
This was a work-time problem where the eating of chocolate was the work, the days showed the time, and the dragons were the workers, all equally efficient.
Learn more about work-time problems at
https://brainly.com/question/7456448
#SPJ2
