Respuesta :

Answer:

area of trapezium=½{a+b}h

½(10+12)6

22*3

66cm²

area of rectangle= l*b

6*5

30cm²

area of unshaded portion= area of trapezium - area of rectangle

(66-30)cm²

36cm²

Area of shaded part is 30cm² and area of unshaded part is 36cm² for the given figure

Area of Trapezium and Area of Rectangle

The given figure is a rectangle inside a trapezium.

The rectangle is the shaded part while the trapezium is the sum of the shaded and the unshaded part of the figure.

We know that Area of rectangle is given by

A =  L x B

where L=Length of rectangle

B=Breadth of rectangle

Given rectangle has L=6cm and B=5cm

Area of rectangle = L x B

                              = 6 x 5

                              = 30cm²

which also gives the area of shaded part of the given figure.

Now, area of trapezium

        =Height(h)*{(Length of smaller side(a) + length of longer side(b)) ÷ 2}

        =h*{(a+b) ÷ 2}

        =6*{(10+12) ÷ 2)

        = 66cm²

which gives the area of trapezium.

Area of unshaded part = Area of trapezium - Area of rectangle

                                      = 66 - 30

                                      = 36cm²

Hence, area of shaded part is 30cm² and area of unshaded part is 36cm² for the given figure.

For more information on this topic, you can refer to

https://brainly.ph/question/4196108

https://brainly.in/question/665085

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