WILL MARK BRAINLIEST!! NEED HELP ASAP

A plane leaves airport A and travels 550 miles to airport B on a bearing of N36°E. The plane later leaves airport B and travels to airport C 390 miles away on a bearing of S73°E. Find the distance from airport A to airport C to the nearest tenth of a mile.

The square of a side of a plane triangle equals the sum of the squares of the remaining sides minus twice the product of those sides and the cosine of the angle between them.

Let x is the distance from airport A to airport C.

The other angle is,

= 73+36

= 109

Now, using cosine law,

x² = 550² + 390² - 2(550)(390)cos(109)

x²= 454600 + 139668.73

x= 770.88 miles

Learn more about this concept here:

https://brainly.com/question/13625569

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WILL MARK BRAINLIEST!! NEED HELP ASAP A plane leaves airport A and travels 550 miles to airport B on a bearing of N36°E. The plane later leaves airport B and travels to airport C 390 miles away on a bearing of S73°E. Find the distance from airport A to airport C to the nearest tenth of a mile.

Respuesta :

What is Cosine law?

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WILL MARK BRAINLIEST!! NEED HELP ASAP

A plane leaves airport A and travels 550 miles to airport B on a bearing of N36°E. The plane later leaves airport B and travels to airport C 390 miles away on a bearing of S73°E. Find the distance from airport A to airport C to the nearest tenth of a mile.