There are 41.04 grams present in 3.24 x 10²³ molecules of carbon disulfide.
- Applying the mole concept:
Number of moles(n) = given mass(m) / molar mass(M)
Number of molecules(N) = number of moles x Avagardo number(Nₐ)
It can also be written as, N = (m/M) x Nₐ
- Avagardo's number, Nₐ = 6.02 x 10²³ molecules/ions/atoms
Molar mass of a molecule= sum of atomic mass of indiviual atoms present in that molecule per mole
Molar mass of CS₂ = atomic mass of Carbon + 2xatomic mass of Sulphur
M = 12 + 2 x 32 = 12 + 64
M = 76 g/mol
- Now applying the formula for the number of molecules-
i.e. N = (m/M) x Na
As per question, N = 3.24 x 10²³ molecules
3.24 x 10²³ = (m/76) x 6.02 x 10²³
m/76 = 3.24 x 10²³ / 6.02 x 10²³
m / 76 = 3.24 / 6.02
m / 76 = 0.54
m = 0.54 x 76
m = 41.04
m = 41.04 grams
Hence, 41.04 grams are present in 3.24 x 10²³ molecules of carbon disulphide.
To learn more about the mole concept, refer to:
https://brainly.com/question/23982593
#SPJ2
