The mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
What is the equation of the synthesis of water from hydrogen and oxygen?
The equation of the synthesis of water from hydrogen and oxygen is given as follows:
- [tex]2\:H_{2} + O_{2}\rightarrow2\:H_{2}O[/tex]
The grams of oxygen required is given below:
[tex]19.2 g\:of H_{2} \times\frac{1\:mol H_{2}}{18 g\:H_{2}} \times\frac{1mol\:O_{2}}{2 mol\:H_{2}}\times\frac{32g\:O_{2}}{1 mol\:O_{2}} = 17.06 g\: O_{2}[/tex]
The equation of the combustion of propane is given as follows:
[tex]C_{3}H_{8} + 5\:O_{2}\rightarrow3\:CO_{2}+4\:H_{2}O[/tex]
The mass of carbon dioxide produced is given below:
[tex]100 g\:of\:C_{3}H_{8} \times\frac{1\:mol\:C_{3}H_{8}}{44 g\:C_{3}H_{8}} \times\frac{3\:mol\:CO_{2}}{1\:mol\:C_{3}H_{8}}\times\frac{44g\:CO_{2}}{1 mol\:CO_{2}} = 300 g\:CO_{2}[/tex]
The equation of the reaction of copper and silver nitrate is given as follows:
[tex]Cu + 2\:AgNO_{3}\rightarrow Cu(NO_{3})_{2} + 2\:Ag[/tex]
[tex]5.7 g\:Cu \times\frac{1\:mol\:Cu}{64 g\:Cu} \times\frac{1mol\:Cu(NO_{3})_{2}}{1mol\:Cu}\times\frac{188g\:Cu(NO_{3})_{2}}{1 mol\:Cu(NO_{3})_{2}} = 16.7 g\:Cu(NO_{3})_{2}[/tex]
Therefore, the mass of oxygen required is 17.06 g; the mass of carbon dioxide produced is 300 g; the mass of copper (ii) nitrate produced is 16.7 g.
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