Answer:
After 9 more minutes, her cell battery will be 80% charged.
Explanation:
Let us try to make an equation here to describe the relation between battery and time.
It is given that the battery charges at a constant rate so we can assume that
battery([tex]b[/tex]) ∝ Time([tex]t[/tex])
[tex]\Rightarrow b=kt[/tex]
But at t=0, the battery is already 30% charged so we rewrite the equation as follows:
[tex]b=kt+30[/tex] -(1)
Now,
at put t=36 and b=70 in Eqn 1:
We get [tex]k=\frac{10}{9}[/tex]
The final eqn is [tex]b=\frac{10}{9}t +30[/tex]
Put b=80
We get:
[tex]\Rightarrow80=\frac{10}{9} t+30\\\Rightarrow 50=\frac{10}{9}t\\\\\Rightarrow t=45 \text{min}[/tex]
∴ It will take (45-36)=9 more minutes to reach 80% battery.
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