The volume V of the solid obtained by rotating the region bounded by the given curves about the x-axis will be V = 149.2.
From the question.
x = 5 + y2,
x = 0,
y = 2,
y = 3
The equation for the volume is mathematically given as
[tex]V = \int\limits^3_2 (2\pi y)(5+y^2) \, dy \\\\\\V = 2\pi \int\limits^3_2(5y+y^3) \, dy \\\\\\V = 2\pi \frac{5y^2}{2} + \frac{y^4}{4} |^3_2\\\\\\V = 149.2[/tex]
Therefore
The volume V of the solid obtained by rotating the region bounded by the given curves about the x-axis will be V = 149.2.
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