Question

1.

Write the equation of the line, in slope - intercept form, that goes through the point ( 12, 5 ) and is perpendicular to the line: y = - 6x - 14.

Answer 1

The equation of the line is y = 1/6x + 3

How to determine the equation?

The equation of the line is given as:

y = -6x - 14

The above equation has a slope of

m = -6

Let the slope of the other line be n.

So, we have:

n =-1/m ---- slope condition for perpendicular lines

So, we have:

n = 1/6

The equation is then calculated as:

y = n(x - x1) + y1

Where

(x1, y1) = (12,5)

This gives

y = 1/6(x - 12) + 5

Expand

y = 1/6x - 2 + 5

Evaluate the sum

y = 1/6x + 3

Hence, the equation of the line is y = 1/6x + 3

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