Question

where Q represents the quantity remaining after tyears and kis the decay
constant 0.00043. How long will take for 500g of radium to decay to 5g?

Answer 1

The number of years for 500g of radium to decay to 5g will be 0.6 years.

What is an exponent?

Let b is the base and n is the power of the exponent function and a is the leading coefficient. The exponent is given as

y = a(b)ⁿ

The quantity (Q) remaining after t years and k is the decay constant 0.00043.

Then the exponent function will be

$\rm Q = 500 * (0.00043)^t$

Then the number of years for 500g of radium to decay to 5g will be

$\rm 5 \ \ \ \ = 500 * (0.00043)^t\\\\0.01 = 0.00043^t$

Taking log on both sides, then we have

t × log 0.00043 = log 0.01

                     t = 0.594 ≈ 0.6 years

More about the exponent link is given below.

https://brainly.com/question/5497425

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