Question

How many numbers less than 904 are divisible by 3?

Answer 1

$\Rightarrow T(n) = a + (n - 1)d$

$\Rightarrow 903 = 3 + (n - 1)3$

$\Rightarrow 903 = 3 + 3n - 3$

$\Rightarrow 3n = 903$

$\Rightarrow n = 301$

$A: 301$

Answer 2

There are 301 numbers less than 904 divisible by 3, as per arithmetic progression.

What is an arithmetic progression?

"Arithmetic Progression is a sequence of numbers in order, in which the difference between any two consecutive numbers is a constant value."

Let, there are 'n' terms less than 904 divisible by 3.

Now, the first term divisible by 3 is(a) = 3.

The second term divisible by 3 is = 6.

Therefore, the common difference between terms divisible by 3 is(d)

$= 6-3\\= 3$

The last term that is less than 904 and divisible by 3 is($T_{n}$) 903.

Now, if we compare it with arithmetic progression, then:

$T_{n} = a + (n - 1)d$

⇒ $903 = 3 + (n-1)3$

⇒ $3(n -1) = 900$

⇒ $n - 1 = 300$

⇒ $n = 301$

The required number is 301.

Learn more about arithmetic progression here: https://brainly.com/question/24873057

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