The statement that -6 is in the domain of f(g(x)) is true
If f(x) = -2x + 8 and g(x) = [tex]\sqrt{x + 9[/tex], which statement is true?
We have:
f(x) = -2x + 8
[tex]g(x) = \sqrt{x + 9[/tex]
Start by calculating the function f(g(x)) using:
f(g(x)) = -2g(x) + 8
Substitute [tex]g(x) = \sqrt{x + 9[/tex]
[tex]f(g(x)) = -2\sqrt{x + 9} + 8[/tex]
Set the radicand to at least 0
[tex]x + 9 \ge 0[/tex]
Subtract 9 from both sides
[tex]x \ge -9[/tex]
This means that the domain of f(g(x)) are real numbers greater than or equal to -9. i.e. -9, -8, -7, -6, ...........
Hence, the statement that -6 is in the domain of f(g(x)) is true
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