Question

The center of an airplane propeller is 13 feet off the ground and the radius of the propeller is 3 feet. The blades of the propeller are set at radians from 0 radians directly to the right of the center of the propeller.

Answer 1

The motion of the blades of the propeller is given by:

f(x) = 3ft*sin(kx) + 13ft

Which equation describes the motion of the blades?

It will be described by a sine function of the form:

f(x) = B*sin(k*x) + M

M is the midpoint, which coincides with the center of the propeller, so M = 13ft.

The amplitude B will be equal to the radius, B = 3ft.

And we know that when x = 0 (at the initial time) the propeller is set to the right, that is why we use a sine function, that becomes zero when x = 0.

Finally, the constant k will be related to the frequency, and it will depend on how fast the blades move.

f(x) = 3ft*sin(kx) + 13ft

If you want to learn more about sine functions:

https://brainly.com/question/9565966

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