Question

x^2-7x-34=10 solve this equation using factorising and soling quadratics

Answer 1

Answer:

$x=-7; x=11$

Step-by-step explanation:

Let's bring 10 to the LHS first.

$x^2-7x-44=0$.

At this point we need two numbers that add to -7 and multiply to -44. From the signs we can tell that the greater of the two is negative, and the smaller is positive. Furthermore, since $44=11\times 4$  we found our two suspects: -11 and 4 (which indeed add up to -7)

Now we can factorize the equation as

$(x-11)(x+4) =0$

which tells us that either $x-11=0 \rightarrow x=11$ or $x+7=0 \rightarrow x=-7$