hi can i please have some help w/ these! i have my exam tomorrow!!! factoring algebra 2! worth 35 points!
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Answer:
11. [tex]4x^{3}-10x^{2}+6x[/tex]
Take out 2x ( greatest common factor )
[tex]2x(2x^{2}-5x+3)[/tex]
Factor
[tex]2x(2x^{2} -2x-3x+3)[/tex]
[tex]2x(x-1)-3(x-1)=(2x-3)(x-1)[/tex]
Don't forget about the 2x we took out earlier
Solution to 11: [tex]2x(2x-3)(x-1)[/tex]
12. [tex]16x^{2} -25y^{2}[/tex]
This is the difference of squares, so let's use the formula...
[tex]a^{2}-b^{2}=(a-b)(a+b)[/tex]
if, [tex]a=16x^{2}[/tex] and [tex]b=25y^{2}[/tex]
then, the Solution to 12 is:
[tex](4x-5y)(4x+5y)[/tex]
13. [tex]3x^3-24[/tex]
First of all, you must find the greatest common factor because there isn't anything else you can do.
[tex]3(x^3-8)[/tex]
Now you can see the difference of cubes...
[tex]a^3-b^3=(a-b)(a^2+ab+b^2)[/tex]
so, the Solution to 13 is:
[tex]3(x^3-8)= 3(x-2)(x^2+2x+4)[/tex]