Question

Frieda stands on a hill with a slope of 62°. If her mass is 49 kg, what is the
magnitude of the normal force acting on her?
A. 480 N
B. 512 N
C. 424 N
D. 226 N

Answer 1

D. The magnitude of the normal force acting on Frieda is approximately 226 N.

Magnitude of Frieda's normal force

The magnitude of the normal force acting on Frieda is calculated as follows;

Fₙ = mgcosθ

where;

• m is mass of Frieda
• g is acceleration due to gravity
• θ is inclination of the slope

Fₙ = (49)(9.81)cos(62)

Fₙ = 225.7 N

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