(15) Mona has x number of quarters and y number of dimes which total $4.75. Gina has y number of quarters and x number of dimes which total $4.00. How many dimes does Gina have?

Word problems in mathematics are real-life situations that can be solved with the use of mathematical expressions (such as algebraic expressions) with the use of variables and their arithmetic operations.

Given that:

Mona: (x)q + (y)d = 4.75 ----- (1)
Gina: (y)q + (x)d = 4.00 ----- (2)

From equation (2), since the number of coins Mona has did not influence Gina's Coin;

The number of dimes Gina has is:

(x)d = 4.00 - (y)q

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(15) Mona has x number of quarters and y number of dimes which total $4.75. Gina has y number of quarters and x number of dimes which total $4.00. How many dimes does Gina have?​

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(15) Mona has x number of quarters and y number of dimes which total $4.75. Gina has y number of quarters and x number of dimes which total $4.00. How many dimes does Gina have?