Question

In the following reaction, how many grams of silver can be produced from 49.1 g copper?

Cu(s) + 2AgNO3(aq) ® 2Ag(s) + Cu(NO3)2(aq)

Answer 1

166.4 g Ag grams of silver can be produced from 49.1 g of copper.

What is a mole?

A mole is a very important unit of measurement that chemists use. A mole of something means you have 602,214,076,000,000,000,000,000 of that thing, like how having a dozen eggs means you have twelve eggs.

$1 mol Cu + 2 mol AgNO_3$ → $2 mol Ag + 1 mol Cu(NO3)2$

63.55 g Cu —> 2 x 107.688 g Ag

63.55 g Cu gives 215.376 g of Ag

So, 49.1 g Cu —> $\frac{215.376 g X 49.1 g}{63.55 g}$

= 166.4 g Ag

Hence, 166.4 g Ag grams of silver can be produced from 49.1 g of copper.

Learn more about moles here:

https://brainly.com/question/26416088

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